2x^2+30-16x=0

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Solution for 2x^2+30-16x=0 equation: 



2x^2+30-16x=0

a = 2; b = -16; c = +30;
Δ = b2-4ac
Δ = -162-4·2·30
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4}{2*2}=\frac{12}{4}
=3
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4}{2*2}=\frac{20}{4}
=5
$

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